F2 Science Electricity Exercise Top !new!

What is the total resistance of the circuit? (Use ( V = IR ))

Explanation: Total current = Sum of branch currents. ( I_{total} = 3A + 1.5A = 4.5A ). f2 science electricity exercise top

Explanation: Branch 2: V=9V, R=6Ω. I = 9/6 = 1.5A. What is the total resistance of the circuit

Three identical bulbs are connected in parallel to a 6V battery. What is the voltage across each bulb? A) 2V B) 3V C) 6V D) 18V Explanation: Branch 2: V=9V, R=6Ω

Calculate the current flowing through Branch 1. (( I = V/R )) Q8. Calculate the current flowing through Branch 2. Q9. Calculate the total current drawn from the battery. Q10. Top Question: If you add a third bulb in parallel to the first two, what happens to the brightness of the original two bulbs? Explain why. Answer Key & Detailed Explanations Do not just check the answer; read the why .

Draw the circuit diagram for the description above. (Answer key: Draw a rectangle. Cell on the left, ammeter on top, L1 on right, L2 on bottom, all in one closed loop). Section C: Parallel Circuit Challenge (Top Difficulty) Circuit: A 9V battery connected to two parallel branches. Branch 1 has a single 3Ω resistor. Branch 2 has a single 6Ω resistor.

Explanation: In a series circuit, there is only one path for electrons. The number of electrons passing point A per second equals the number passing point B. Current is constant.